Use Oxygen level (%) -App in your Suunto watch.

radku

Made this one!
Munich, Germany
535 Moves, 36 fans

Oxygen level (%)

30.11.2012

Mountaineering, Guidance

Oxygen level at the given altitude as percentage of maximum at the see level. Formula: (1+H+(H^2)/2+(H^3)/6+(H^4)/24)*100, with H = -ALTITUDE/7990

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10 latest Moves using this App

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  • juniortipay

    28.4.2014

    can anyone tell me how to sync this app to my AMBIT2. thanks

  • RAULBANDERAS

    16.1.2014

    In the test it only works up to 5000 meters. My question is if it works at higher altitudes?

    thank you

    • radku

      16.1.2014

      I'm afraid not. I have tested it in himalaya and it works only up to 5000m. It's because the alti value is programmatically limited by suunto.

  • scase313

    6.1.2014

    This may not be accurate everywhere, even if you use barometric pressure. The latitude of your location has a lot to do with the equation since the atmosphere is thinner as you go further South or further North toward the poles. This is a significant change in places like Alaska, USA. Further, since the Suunto does not show true barometric pressure, but adjusted pressure, a calculation using pressure won't be accurate either.

  • ChrisYeoJoonKiat

    13.12.2013

    % of O2 in Air is about 21% at Sea Level. Should the figure shown be a true reflect of this and decreasing as we ascend, i.e. e.g. @3374m, approximate % of O2 in Air decreases to 13.8%?

    • Xydal

      3 weeks ago

      Proportion of O2 remain the same with altitude at about 21%. It's the density/pressure which decrease meaning there is less molecules of air. So at 0m you have 100% of the molecules and higher you get, that % decrease.

  • 240RS

    27.9.2013

    Love the application! But I always looked a pressure.

    Isn't the %O2 proportional to the absolute pressure? So that O2% = SUUNTO_PRESSURE /1013*100? Or did I miss something?

    • radku

      7.10.2013

      Of course you are right. Pressure measurement is programmatically limited, so I tried to go out of the boundaries using altitude. It didn't work because altitude is deviated from pressure :-)

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